Optimal. Leaf size=333 \[ -\frac{15 d^{11/2} \log \left (-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}+\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x\right )}{256 \sqrt{2} a^{3/4} b^{13/4}}+\frac{15 d^{11/2} \log \left (\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}+\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x\right )}{256 \sqrt{2} a^{3/4} b^{13/4}}-\frac{15 d^{11/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{128 \sqrt{2} a^{3/4} b^{13/4}}+\frac{15 d^{11/2} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}+1\right )}{128 \sqrt{2} a^{3/4} b^{13/4}}-\frac{15 d^5 \sqrt{d x}}{64 b^3 \left (a+b x^2\right )}-\frac{3 d^3 (d x)^{5/2}}{16 b^2 \left (a+b x^2\right )^2}-\frac{d (d x)^{9/2}}{6 b \left (a+b x^2\right )^3} \]
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Rubi [A] time = 0.344579, antiderivative size = 333, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 9, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.321, Rules used = {28, 288, 329, 211, 1165, 628, 1162, 617, 204} \[ -\frac{15 d^{11/2} \log \left (-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}+\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x\right )}{256 \sqrt{2} a^{3/4} b^{13/4}}+\frac{15 d^{11/2} \log \left (\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}+\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x\right )}{256 \sqrt{2} a^{3/4} b^{13/4}}-\frac{15 d^{11/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{128 \sqrt{2} a^{3/4} b^{13/4}}+\frac{15 d^{11/2} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}+1\right )}{128 \sqrt{2} a^{3/4} b^{13/4}}-\frac{15 d^5 \sqrt{d x}}{64 b^3 \left (a+b x^2\right )}-\frac{3 d^3 (d x)^{5/2}}{16 b^2 \left (a+b x^2\right )^2}-\frac{d (d x)^{9/2}}{6 b \left (a+b x^2\right )^3} \]
Antiderivative was successfully verified.
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Rule 28
Rule 288
Rule 329
Rule 211
Rule 1165
Rule 628
Rule 1162
Rule 617
Rule 204
Rubi steps
\begin{align*} \int \frac{(d x)^{11/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx &=b^4 \int \frac{(d x)^{11/2}}{\left (a b+b^2 x^2\right )^4} \, dx\\ &=-\frac{d (d x)^{9/2}}{6 b \left (a+b x^2\right )^3}+\frac{1}{4} \left (3 b^2 d^2\right ) \int \frac{(d x)^{7/2}}{\left (a b+b^2 x^2\right )^3} \, dx\\ &=-\frac{d (d x)^{9/2}}{6 b \left (a+b x^2\right )^3}-\frac{3 d^3 (d x)^{5/2}}{16 b^2 \left (a+b x^2\right )^2}+\frac{1}{32} \left (15 d^4\right ) \int \frac{(d x)^{3/2}}{\left (a b+b^2 x^2\right )^2} \, dx\\ &=-\frac{d (d x)^{9/2}}{6 b \left (a+b x^2\right )^3}-\frac{3 d^3 (d x)^{5/2}}{16 b^2 \left (a+b x^2\right )^2}-\frac{15 d^5 \sqrt{d x}}{64 b^3 \left (a+b x^2\right )}+\frac{\left (15 d^6\right ) \int \frac{1}{\sqrt{d x} \left (a b+b^2 x^2\right )} \, dx}{128 b^2}\\ &=-\frac{d (d x)^{9/2}}{6 b \left (a+b x^2\right )^3}-\frac{3 d^3 (d x)^{5/2}}{16 b^2 \left (a+b x^2\right )^2}-\frac{15 d^5 \sqrt{d x}}{64 b^3 \left (a+b x^2\right )}+\frac{\left (15 d^5\right ) \operatorname{Subst}\left (\int \frac{1}{a b+\frac{b^2 x^4}{d^2}} \, dx,x,\sqrt{d x}\right )}{64 b^2}\\ &=-\frac{d (d x)^{9/2}}{6 b \left (a+b x^2\right )^3}-\frac{3 d^3 (d x)^{5/2}}{16 b^2 \left (a+b x^2\right )^2}-\frac{15 d^5 \sqrt{d x}}{64 b^3 \left (a+b x^2\right )}+\frac{\left (15 d^4\right ) \operatorname{Subst}\left (\int \frac{\sqrt{a} d-\sqrt{b} x^2}{a b+\frac{b^2 x^4}{d^2}} \, dx,x,\sqrt{d x}\right )}{128 \sqrt{a} b^2}+\frac{\left (15 d^4\right ) \operatorname{Subst}\left (\int \frac{\sqrt{a} d+\sqrt{b} x^2}{a b+\frac{b^2 x^4}{d^2}} \, dx,x,\sqrt{d x}\right )}{128 \sqrt{a} b^2}\\ &=-\frac{d (d x)^{9/2}}{6 b \left (a+b x^2\right )^3}-\frac{3 d^3 (d x)^{5/2}}{16 b^2 \left (a+b x^2\right )^2}-\frac{15 d^5 \sqrt{d x}}{64 b^3 \left (a+b x^2\right )}-\frac{\left (15 d^{11/2}\right ) \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d}}{\sqrt [4]{b}}+2 x}{-\frac{\sqrt{a} d}{\sqrt{b}}-\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt{d x}\right )}{256 \sqrt{2} a^{3/4} b^{13/4}}-\frac{\left (15 d^{11/2}\right ) \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d}}{\sqrt [4]{b}}-2 x}{-\frac{\sqrt{a} d}{\sqrt{b}}+\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt{d x}\right )}{256 \sqrt{2} a^{3/4} b^{13/4}}+\frac{\left (15 d^6\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{a} d}{\sqrt{b}}-\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt{d x}\right )}{256 \sqrt{a} b^{7/2}}+\frac{\left (15 d^6\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{a} d}{\sqrt{b}}+\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt{d x}\right )}{256 \sqrt{a} b^{7/2}}\\ &=-\frac{d (d x)^{9/2}}{6 b \left (a+b x^2\right )^3}-\frac{3 d^3 (d x)^{5/2}}{16 b^2 \left (a+b x^2\right )^2}-\frac{15 d^5 \sqrt{d x}}{64 b^3 \left (a+b x^2\right )}-\frac{15 d^{11/2} \log \left (\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}\right )}{256 \sqrt{2} a^{3/4} b^{13/4}}+\frac{15 d^{11/2} \log \left (\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x+\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}\right )}{256 \sqrt{2} a^{3/4} b^{13/4}}+\frac{\left (15 d^{11/2}\right ) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{128 \sqrt{2} a^{3/4} b^{13/4}}-\frac{\left (15 d^{11/2}\right ) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{128 \sqrt{2} a^{3/4} b^{13/4}}\\ &=-\frac{d (d x)^{9/2}}{6 b \left (a+b x^2\right )^3}-\frac{3 d^3 (d x)^{5/2}}{16 b^2 \left (a+b x^2\right )^2}-\frac{15 d^5 \sqrt{d x}}{64 b^3 \left (a+b x^2\right )}-\frac{15 d^{11/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{128 \sqrt{2} a^{3/4} b^{13/4}}+\frac{15 d^{11/2} \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{128 \sqrt{2} a^{3/4} b^{13/4}}-\frac{15 d^{11/2} \log \left (\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}\right )}{256 \sqrt{2} a^{3/4} b^{13/4}}+\frac{15 d^{11/2} \log \left (\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x+\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}\right )}{256 \sqrt{2} a^{3/4} b^{13/4}}\\ \end{align*}
Mathematica [A] time = 0.131344, size = 299, normalized size = 0.9 \[ \frac{d^5 \sqrt{d x} \left (-\frac{3840 a^2 \sqrt [4]{b}}{\left (a+b x^2\right )^3}-\frac{315 \sqrt{2} \log \left (-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{a}+\sqrt{b} x\right )}{a^{3/4} \sqrt{x}}+\frac{315 \sqrt{2} \log \left (\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{a}+\sqrt{b} x\right )}{a^{3/4} \sqrt{x}}-\frac{630 \sqrt{2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}\right )}{a^{3/4} \sqrt{x}}+\frac{630 \sqrt{2} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}+1\right )}{a^{3/4} \sqrt{x}}-\frac{7168 b^{9/4} x^4}{\left (a+b x^2\right )^3}-\frac{9216 a b^{5/4} x^2}{\left (a+b x^2\right )^3}+\frac{840 \sqrt [4]{b}}{a+b x^2}+\frac{480 a \sqrt [4]{b}}{\left (a+b x^2\right )^2}\right )}{10752 b^{13/4}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.064, size = 280, normalized size = 0.8 \begin{align*} -{\frac{113\,{d}^{7}}{192\, \left ( b{d}^{2}{x}^{2}+a{d}^{2} \right ) ^{3}b} \left ( dx \right ) ^{{\frac{9}{2}}}}-{\frac{21\,{d}^{9}a}{32\, \left ( b{d}^{2}{x}^{2}+a{d}^{2} \right ) ^{3}{b}^{2}} \left ( dx \right ) ^{{\frac{5}{2}}}}-{\frac{15\,{d}^{11}{a}^{2}}{64\, \left ( b{d}^{2}{x}^{2}+a{d}^{2} \right ) ^{3}{b}^{3}}\sqrt{dx}}+{\frac{15\,{d}^{5}\sqrt{2}}{512\,a{b}^{3}}\sqrt [4]{{\frac{a{d}^{2}}{b}}}\ln \left ({ \left ( dx+\sqrt [4]{{\frac{a{d}^{2}}{b}}}\sqrt{dx}\sqrt{2}+\sqrt{{\frac{a{d}^{2}}{b}}} \right ) \left ( dx-\sqrt [4]{{\frac{a{d}^{2}}{b}}}\sqrt{dx}\sqrt{2}+\sqrt{{\frac{a{d}^{2}}{b}}} \right ) ^{-1}} \right ) }+{\frac{15\,{d}^{5}\sqrt{2}}{256\,a{b}^{3}}\sqrt [4]{{\frac{a{d}^{2}}{b}}}\arctan \left ({\sqrt{2}\sqrt{dx}{\frac{1}{\sqrt [4]{{\frac{a{d}^{2}}{b}}}}}}+1 \right ) }+{\frac{15\,{d}^{5}\sqrt{2}}{256\,a{b}^{3}}\sqrt [4]{{\frac{a{d}^{2}}{b}}}\arctan \left ({\sqrt{2}\sqrt{dx}{\frac{1}{\sqrt [4]{{\frac{a{d}^{2}}{b}}}}}}-1 \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.42012, size = 841, normalized size = 2.53 \begin{align*} \frac{180 \,{\left (b^{6} x^{6} + 3 \, a b^{5} x^{4} + 3 \, a^{2} b^{4} x^{2} + a^{3} b^{3}\right )} \left (-\frac{d^{22}}{a^{3} b^{13}}\right )^{\frac{1}{4}} \arctan \left (-\frac{\left (-\frac{d^{22}}{a^{3} b^{13}}\right )^{\frac{3}{4}} \sqrt{d x} a^{2} b^{10} d^{5} - \sqrt{d^{11} x + \sqrt{-\frac{d^{22}}{a^{3} b^{13}}} a^{2} b^{6}} \left (-\frac{d^{22}}{a^{3} b^{13}}\right )^{\frac{3}{4}} a^{2} b^{10}}{d^{22}}\right ) + 45 \,{\left (b^{6} x^{6} + 3 \, a b^{5} x^{4} + 3 \, a^{2} b^{4} x^{2} + a^{3} b^{3}\right )} \left (-\frac{d^{22}}{a^{3} b^{13}}\right )^{\frac{1}{4}} \log \left (15 \, \sqrt{d x} d^{5} + 15 \, \left (-\frac{d^{22}}{a^{3} b^{13}}\right )^{\frac{1}{4}} a b^{3}\right ) - 45 \,{\left (b^{6} x^{6} + 3 \, a b^{5} x^{4} + 3 \, a^{2} b^{4} x^{2} + a^{3} b^{3}\right )} \left (-\frac{d^{22}}{a^{3} b^{13}}\right )^{\frac{1}{4}} \log \left (15 \, \sqrt{d x} d^{5} - 15 \, \left (-\frac{d^{22}}{a^{3} b^{13}}\right )^{\frac{1}{4}} a b^{3}\right ) - 4 \,{\left (113 \, b^{2} d^{5} x^{4} + 126 \, a b d^{5} x^{2} + 45 \, a^{2} d^{5}\right )} \sqrt{d x}}{768 \,{\left (b^{6} x^{6} + 3 \, a b^{5} x^{4} + 3 \, a^{2} b^{4} x^{2} + a^{3} b^{3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.32454, size = 412, normalized size = 1.24 \begin{align*} \frac{1}{1536} \, d^{4}{\left (\frac{90 \, \sqrt{2} \left (a b^{3} d^{2}\right )^{\frac{1}{4}} d \arctan \left (\frac{\sqrt{2}{\left (\sqrt{2} \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}} + 2 \, \sqrt{d x}\right )}}{2 \, \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}}}\right )}{a b^{4}} + \frac{90 \, \sqrt{2} \left (a b^{3} d^{2}\right )^{\frac{1}{4}} d \arctan \left (-\frac{\sqrt{2}{\left (\sqrt{2} \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}} - 2 \, \sqrt{d x}\right )}}{2 \, \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}}}\right )}{a b^{4}} + \frac{45 \, \sqrt{2} \left (a b^{3} d^{2}\right )^{\frac{1}{4}} d \log \left (d x + \sqrt{2} \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}} \sqrt{d x} + \sqrt{\frac{a d^{2}}{b}}\right )}{a b^{4}} - \frac{45 \, \sqrt{2} \left (a b^{3} d^{2}\right )^{\frac{1}{4}} d \log \left (d x - \sqrt{2} \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}} \sqrt{d x} + \sqrt{\frac{a d^{2}}{b}}\right )}{a b^{4}} - \frac{8 \,{\left (113 \, \sqrt{d x} b^{2} d^{7} x^{4} + 126 \, \sqrt{d x} a b d^{7} x^{2} + 45 \, \sqrt{d x} a^{2} d^{7}\right )}}{{\left (b d^{2} x^{2} + a d^{2}\right )}^{3} b^{3}}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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